Question:
Calculate the mass of silver metal {eq}\rm (Ag) {/eq} produced from the reaction of {eq}5.58 {/eq} grams of copper metal {eq}\rm (Cu) {/eq} according to the following reaction: {eq}\rm Cu(s) + 2AgNO_3(aq) \to Cu(NO_3)_2(aq) + 2Ag(s) {/eq}.
Molar Ratio:
The molar ratio between substances depicts the ratio that provides a conversion factor to determine the number of moles of one substance that corresponds to another in a given chemical reaction or formula. The molar ratio is simply the ratio between the coefficients of the involved substances in a given balanced chemical reaction.
Answer and Explanation: 1
Determine the mass of silver metal, {eq}\displaystyle m_{Ag} {/eq}, from the given amount of copper metal, by multiplying the given the mass of Cu,...
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Writing Balanced Chemical Reactions
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Chapter 2 / Lesson 14
When a chemical reaction is balanced, both sides of the equation have the same number and type of atoms. In this lesson, explore the components of a chemical equation and learn how to write balanced chemical reactions.
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Explanation:
The reaction is:
#Cu(s)+AgNO_3(aq)->Ag(s)+CuNO_3(aq)#
Since the silver nitrate is in excess, then copper is the limiting reactant , and therefore, its mass will be used to calculate the mass of silver that will form:
#?gAg=40.0cancel(gCu)xx(cancel(1molCu))/(63.5cancel(gCu))xx(1cancel(molAg))/(1cancel(molCu))xx(107.9Ag)/(1cancel(molAg))=68.0gAg#
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1 Expert Answer
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J.R. S. answered • 01/27/21
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Write the balanced equation:
Cu(s) + 2AgNO3(aq) ==> Cu(NO3)2(aq) + 2Ag(s)
moles Cu present = 100. g Cu x 1 mol Cu/63.55 g = 1.574 moles Cu
mass of Ag produced = 1.574 mol Cu x 2 mol Ag / 1 mol Cu x 107.9 g Ag / mol Ag = 340. g Ag
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